250=1.2v+v^2

Solution for 250=1.2v+v^2 equation:

250=1.2v+v^2

We move all terms to the left:

250-(1.2v+v^2)=0

We get rid of parentheses

-v^2-1.2v+250=0

We add all the numbers together, and all the variables

-1v^2-1.2v+250=0

a = -1; b = -1.2; c = +250;
Δ = b2-4ac
Δ = -1.22-4·(-1)·250
Δ = 1001.44
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.2)-\sqrt{1001.44}}{2*-1}=\frac{1.2-\sqrt{1001.44}}{-2}
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.2)+\sqrt{1001.44}}{2*-1}=\frac{1.2+\sqrt{1001.44}}{-2}
$